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Author Topic: balancing  (Read 383 times)
pluristiq
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« on: 02:42 AM - 04/20/08 »

There are 2n+1 real numbers, n\geq 1, with the property that whenever one of them is removed, the remaining 2n can be split into two sets of n elements each so that both sets have the same sum. Prove that all the numbers are equal.
« Last Edit: 02:44 AM - 04/20/08 by pluristiq » Logged

let it be known
Mr. Curious
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« Reply #1 on: 11:49 PM - 01/11/10 »

There are 2n+1 real numbers, n\geq 1, with the property that whenever one of them is removed, the remaining 2n can be split into two sets of n elements each so that both sets have the same sum. Prove that all the numbers are equal.
Attached is a solution to this balancing problem that is readable in Wordpad but not when pasted into this chatting space. The formatting looks bad in MS Word also, so please use Wordpad to open this file. The topic may be almost two years old, but the problem is still worth focused attention by any curious math student, in that it stimulates explorations in unfamiliar territory. Cheers!
« Last Edit: 01:49 PM - 01/12/10 by Mr. Curious » Logged
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